Here is another GED Math practice test that allows the use of a calculator. The majority of the GED 2014 Math questions do allow the use of a calculator. As you work through these problems, be sure to review the explanations for any wrong answers. It is very important to learn from your mistakes!
Directions: Solve each problem and select the best answer. You may use your calculator. You may also refer to the GED Formula Sheet as needed.
Begin by finding the women’s contribution to the overall average (recall that 80% = 0.8): 0.8 * 30 = 24
Next, find the men’s contribution: 0.2 * 40 = 8
Combine these to find the overall average: 24 + 8 = 32
Notice that this combined average is between the average age of the women (30) and the average age of the men (40), which makes sense because both groups are contributing to the overall average.
Substitute the known values into their appropriate places and solve for the unknown side length:
33² + 56² = c²
Evaluate the squares:
1,089 + 3,136 = c²
4,225 = c²
Evaluate the square root of both sides:
c = 65
The heaviest player weighs 300 lbs.
One-fourth of the players weigh less than 200 lbs.
The median player weighs 245 lbs.
The lightest player weighs 200 lbs.
In this example, the minimum value represents the lightest player on the team and the maximum value represents the heaviest player on the team. The median value is the player who is at the midpoint of the distribution. The quartile values divide the distribution into fourths. Since the lower quartile is at 200, it is accurate to say that one-fourth of the players weigh less than 200 lbs.
The probability of the team scoring first in 4 straight games is then:
0.9 * 0.9 * 0.9 * 0.9 = 0.6561, which rounds to 0.656.
SA = 2πrh + 2πr²
Recall that π (pi) is approximately equal to 3.14. We have the diameter of the lid, but we need the radius. The radius is equal to half the diameter, so r = 1.5 in. The height is given as h = 6 in:
SA = 2(3.14)(1.5)(6) + 2(3.14)(1.5)²
Use your calculator to solve. Remember your order of operations. Calculate the exponent first, followed by the multiplication, and then the addition:
SA = 2(3.14)(1.5)(6) + 2(3.14)(2.25)
SA = 56.52 + 14.13
SA = 70.65 in²
The given information tells us that Raymond lives 15 miles from Amanda and 23 miles from Chicago. Subtract these quantities to find the distance from Amanda’s house to Chicago: 23 − 15 = 8 miles. Amanda lives halfway between Charlie and Chicago, so the distance between her house and Charlie’s is 8 miles. The distance from Charlie’s house to Chicago is 8 + 8 = 16 miles. If Charlie lives 16 miles from Chicago and Raymond lives 23 miles from Chicago, then the distance between their houses must be 23 − 16 = 7.
Since Charlie’s house is equidistant from Chicago and Hoopertown, the distance from Charlie’s to Hoopertown must also be 16 miles. Raymond lives 7 miles from Charlie so the distance from Raymond’s house to Hoopertown is 16 − 7 = 9 miles.
Substitute the given points (0,5) and (7,0) into the equation to calculate the slope:
y = 4x ÷ 3
y = 2x + 3
y = x + 5
y = 3x2
The answer must be y = 2x + 3. This answer can be further verified by substituting each ordered pair into the equation, for example:
11 = 2(4) + 3
11 = 8 + 3
11 = 11
x * y
y − x
y ÷ x
x ÷ y
An alternative solution is choosing a small negative integer for x, −1, and a large positive integer for y, 100, and substituting these values into each of the answer choices.
$305 − $35.75 = $269.25.
We can then divide this amount by the cost per bag to find the total number of bags that Li can buy:
$269.25 ÷ $7.50 = 35.9 bags. However, the question states that the mulch can only be sold in full bags, so we must round our answer down to ensure that Li does not exceed his budget.
More GED Practice:
GED Math Practice Test 4 >>